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Races and clocks — Practice MCQs

Races, circular tracks, angle between clock hands

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    Practise 33 questions on this topic
    Learn mode or test mode, with explanations
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    1. Races

    In a 100 m race A beats B by 10 m and B beats C by 10 m. When A runs 100, B runs 90, C runs 90 × 0.9 = 81 → A beats C by 19 m.
    A runs 1 km in 3 min, B in 3 min 20 s → A beats B by 20 s; B's speed = 1000/200 = 5 m/s → by 100 m.

    2. Circular track

    Lap times 4, 6 and 10 min → together at start after LCM = 60 min.

    3. Clocks — the basics

    Angle at 3:40 = |90 − 220| = 130°.
    Between 4 and 5, hands together at (20 × 12/11) = 21 9/11 min past 4.

    4. Fast or slow clocks

    A clock loses 5 min every hour. Set right at 6 a.m.; true time when it shows 6 p.m.: it moves 55 min per 60 → 12 h shown = 12 × 60/55 = 13 1/11 h → about 7:05 p.m.

    5. Calendar quick facts

    Solved examples by question type

    Each type that comes in the ASO paper, worked step by step. Try it yourself first, then read the solution.

    ASO exam level

    Example 1. In a 1 km race, A beats B by 28 metres or 5 seconds. A's time over the course is:
    (a) 183.57 s   (b) 173.57 s   (c) 168.57 s   (d) 178.57 s
    Answer: (b) 173.57 s
    Solution: B runs 28 m in 5 s → 5.6 m/s. B's time for 1000 m = 178.57 s. A is 5 s faster: 173.57 s.
    Example 2. A runs 5/4 times as fast as B. In a 100 m race, how much start should A give B so that the race ends in a dead heat?
    (a) 20 m   (b) 25 m   (c) 30 m   (d) 23 m
    Answer: (a) 20 m
    Solution: When A runs 100 m, B runs 100 × 4/5 = 80 m. Start = 100 − 80 = 20 m.

    Advanced level

    Example 3. In a 100 m race, A runs at 9 km/h. A gives B a start of 5 m and still beats him by 15 seconds. B's speed is:
    (a) 7.22 km/h   (b) 6.22 km/h   (c) 5.72 km/h   (d) 6.55 km/h
    Answer: (b) 6.22 km/h
    Solution: A's time = 100 ÷ (9×5/18) = 40 s. B takes 40 + 15 = 55 s for 95 m → 1.73 m/s = 6.22 km/h.
    Example 4. In a 100 m race, A runs at 10 km/h. A gives B a start of 4 m and still beats him by 15 seconds. B's speed is:
    (a) 6.78 km/h   (b) 7.78 km/h   (c) 6.28 km/h   (d) 7.06 km/h
    Answer: (a) 6.78 km/h
    Solution: A's time = 100 ÷ (10×5/18) = 36 s. B takes 36 + 15 = 51 s for 96 m → 1.88 m/s = 6.78 km/h.
    Example 5. A and B start together from the same point and run around a circular track of 1200 m at 6 m/s and 4 m/s in opposite directions. When will they meet for the first time?
    (a) 200 s   (b) 120 s   (c) 240 s   (d) 600 s
    Answer: (b) 120 s
    Solution: Opposite directions: relative speed = 6 + 4 = 10 m/s. First meeting = 1200/10 = 120 s. (Same direction would be 1200/2 = 600 s.)
    Example 6. A and B start together from the same point and run around a circular track of 1200 m at 6 m/s and 4 m/s in opposite directions. When will they meet for the first time?
    (a) 600 s   (b) 200 s   (c) 120 s   (d) 240 s
    Answer: (c) 120 s
    Solution: Opposite directions: relative speed = 6 + 4 = 10 m/s. First meeting = 1200/10 = 120 s. (Same direction would be 1200/2 = 600 s.)
    Example 7. A clock is set right at 5 AM. It loses 16 minutes in 24 hours. What is the true time when the clock shows 10 PM on the 4th day?
    (a) 11:15 PM   (b) 9:44 PM   (c) 10:00 PM   (d) 11:00 PM
    Answer: (d) 11:00 PM
    Solution: Clock time passed = 89 h. Clock shows 1424 min for every 1440 true min. True time passed = 89 × 1440/1424 h → 11:00 PM.

    Topic-wise practice for Races and clocks (Quant): Races, circular tracks, angle between clock hands. Useful for OPSC ASO, OSSC, OSSSC and other Odisha exams.

    Question types covered

    Sourced from the Odisha Public Service Commission where applicable. opsc.gov.in. EduSaint is not affiliated with OPSC.